Well, if I have a gradient field, then if I try to compute this line integral, I know it will be the value of the function at the end point minus the value at the starting point.
如果有一个梯度场,然后想计算线积分,我知道积分值是,起点的函数值减去终点的函数值。
The end test-- and I've got the wrong glasses on but it's up here, where I'm looking to see, is last minus first less than or equal to 2?
最后一次比较,我看错了,在上面,last减去first是不是小于2呢?,好的,既然我得到了一个?
At the end of each month, the amount of money deposited by the user is divided by the number of clicks (minus a 10% fee for Flattr) and distributed among the site owners.
在每个月的月底,用户金所有额是以点击数(减去10%的Flattr费)加上网站所有者之间的分配。
475 Multiply by 1.7475 787kJ/mol and you end up with minus 787 kilojoules per mole.
乘以1。,最终得到。
For the carbon, we start with 4 valence electrons, we have 0 lone pair electrons minus 4, and we end up with a formal charge of 0.
对于碳,我们从四个价电子开始,我们有零个孤对电子,再减去四,最终我们有零个形式电荷。
So I'm first going to look for something that's not in the list, I'm going to see, is minus 1 in this list, so it's going to be at the far end, and if I do that in the basic case, bam.
如果我试试第一种最基本的方法,噢,一下就完成了对不对?,因为这种方法查了下第一个元素,然后发现目标数比较下,因为目标数小于第一个元素。
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